What’s Wrong with This?
Wally `Larman was asked by one of his commercial accounts to add access control to a server room door approximately 200 feet from the access control panel. He carefully selected devices that were compatible with the existing system, including a 24 V 750mA electric strike, satisfied all codes and requirements, and installed them as shown in this diagram. When he was finished, he tested the system and all appeared to be in proper working order, but his customer later called and said that periodically the server room door would not lock. Wally replaced the electric lock, but the problem continued. Can you see what Wally did wrong and what he must do to correct the problem?
Answer to: What's Wrong with This?
Wally’s problem is caused by the size of wire he ran for the electric lock. Using 22 AWG cable for a 200-foot run will cause a voltage drop of approximately 4 volts, which is causing the fail-safe lock to release or decreasing its ability to secure the door. Wally should replace the lock cable with a larger wire, minimum of 18 AWG, reducing the voltage drop to about 2 volts. When designing the cable runs, take into account the length of the run and the current draw of the lock, because these factors will affect how much voltage is lost in the cable (voltage drop). To calculate the voltage drop, you can use Ohm’s Law: voltage = current times resistance.